A cannonball is shot upward from the upper deck of a fort with an initial velocity of 192 feet per second. The deck is 32 feet above the ground.
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This problem can be solved with the equation: h = -16t2+v0t+h0, where h is initial height and v is initial velocity.
So, h = -16t2+192t+32
To solve this equation, I put it in a graphing calculator. The highest point the parabloa reaches on the y-axis is 608, meaning that 608 feet is the highest point the cannonball reached.
To find how long the cannon ball was in the air, you use the quadratic formula, or:
x=(-b±√(b^2-4ac))/2a
To find how long the cannon ball was in the air, you use the quadratic formula, or:
x=(-b±√(b^2-4ac))/2a
a = -16 b = 192 and c = 32
When you plug in these numbers, you get 12.164414, or just over 12 seconds long.
Good job on the math! I got the same answer, so I'm betting that we're right.
ReplyDeletegood job we got the same answer
ReplyDeleteAwesome, I got the exact same answer. Although I did mine another way, just a little simpler ;) Blog looks awesome
ReplyDeleteNice but you should show some more work
ReplyDelete